300x^2+490x-52=0

Solution for 300x^2+490x-52=0 equation:

300x^2+490x-52=0

a = 300; b = 490; c = -52;
Δ = b2-4ac
Δ = 4902-4·300·(-52)
Δ = 302500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{302500}=550$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(490)-550}{2*300}=\frac{-1040}{600}
=-1+11/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(490)+550}{2*300}=\frac{60}{600}
=1/10
$